Engine Fuel Equivalent Power (\(P_{fe}\)):

\[ P_{fe} = \frac{H_f \cdot m_f}{3600} \]

Where:

• \(P_{fe}\) is the fuel equivalent power, kW.
• \(H_f\) is the heating value of fuel, kJ/kg.
• \(m_f\) is the rate of fuel consumption, kg/hr.